4[n-2(3n+5)]=32

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Solution for 4[n-2(3n+5)]=32 equation:


Simplifying
4[n + -2(3n + 5)] = 32

Reorder the terms:
4[n + -2(5 + 3n)] = 32
4[n + (5 * -2 + 3n * -2)] = 32
4[n + (-10 + -6n)] = 32

Reorder the terms:
4[-10 + n + -6n] = 32

Combine like terms: n + -6n = -5n
4[-10 + -5n] = 32
[-10 * 4 + -5n * 4] = 32
[-40 + -20n] = 32

Solving
-40 + -20n = 32

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '40' to each side of the equation.
-40 + 40 + -20n = 32 + 40

Combine like terms: -40 + 40 = 0
0 + -20n = 32 + 40
-20n = 32 + 40

Combine like terms: 32 + 40 = 72
-20n = 72

Divide each side by '-20'.
n = -3.6

Simplifying
n = -3.6

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